### Structural Design for Non-Structural Engineers - EIT ...

50×5 + 5×10(15 +2.5) – R B × 20 = 0. Hence, R B = 56.25 kN. Now, by applying the equation Σ F Y = 0, R A – 50 – 5×10 + 56.25 = 0. Hence, R A = 43.75 kN. Now, with R A and R B known, we will consider three sections along the span of the beam AB to derive the values of the bending moment and shear force along the entire span.

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